In C and Objective-C, the division and modulus operators perform truncation towards zero. So something must be wrong. Prior to C99 standard, % operator's behavior on negative number is implementation defined. The C90 standard does not define the result of modulus applied on negative numbers, so the result is compiler dependant. Modulus of Negative Numbers in C. C Server Side Programming Programming. However, it is perfectly fine to write both $18 \equiv 3 \pmod{5}$ and $18 \equiv -2 \pmod{5}$ as $3 \equiv -2 \pmod{5}$. Any relationship between these properties is highly dependent on the shape in question. The sign of the value returned by the remainder operation depends on the sign of dividend. C# program that uses modulo operator using System; class Program { static void Main() {// When 5 is divided by 3, the remainder is 2.Console.WriteLine(5 % 3); // When 1000 is divided by 90, the remainder is 10.Console.WriteLine(1000 % 90); // When 100 is divided by 90, the remainder is also 10.Console.WriteLine(100 % 90); // When 81 is divided by 80, the remainder is 1. It is commonly used to take a randomly generated number and reduce that number to a random number on a smaller range, and it can also quickly tell you if one number is a factor of another. From C99 onwards the result of % is required to be rounded toward 0 as quoted by Chris Dodd.. The range is clearly the set of all non-negative real numbers, or \(\left( {0,\infty} \right)\). a / b is floor(a / b) if a / b > 0, otherwise it is ceiling(a / b) if a / b < 0.It is always the case that a == (a / b) * b + (a % b), unless of course b is 0. The equivalent method for this operator is Decimal.Remainder(Decimal, Decimal). Think of it like moving a hand around a clock, where every time we get a multiple of N, weâre back at 0. Section modulus is a geometric property for a given cross-section used in the design of beams or flexural members. Example Generically, function objects are instances of a class with member function operator() defined. Of course, if you have HUGE negative numbers (IE -597 or whtaver) then just add a bigger adjustment, for example 600 or 6000 or 60000 will all work -- basically all you are doing is shifting the number into the positive side of the modulus. The modulus operator is useful in a variety of circumstances. Here we will see what will be the result if we use negative numbers to get the modulus. When integers are divided and the division is inexact, if both operands are positive the result of the / operator is the largest integer less than the algebraic quotient and the result of the % operator is positive. This is in line with the piecewise definition of the modulus function. Let us see the following programs and their outputs to get the idea. If dividend is positive, the remainder operation returns a positive result; if it is negative, the remainder operation returns a negative result. Other geometric properties used in design include area for tension and shear, radius of gyration for compression, and moment of inertia and polar moment of inertia for stiffness. Binary function object class whose call returns the result of the modulus operation between its two arguments (as returned by operator %). Since we can apply the modulus operation to any real number, the domain of the modulus function is \(\mathbb{R}\). As it turns out Câs modulo operator behaves differently from the mathematically defined ones when we apply it for negative numbers. To answer the question in your title, the modulus (in your example, it is five) must always be at least $2$ for anything (interesting) to make sense. This member function allows the object to be used with the same syntax as a function call. Specifically, modulus can never be negative. Example 1: A function f is defined on \(\mathbb{R}\) as follows: